Question

Determine algebraically whether the function is even, odd, or neither even nor odd.

f(x) = 3x2 - 1

Answer 1

plug in -x
f(-x)=?
if you get f(-x)=f(x) then f is even
if you get f(-x)=-f(x) then f is odd

Answer 2

if you get neither f(x) or -f(x) then f is neither odd or even

Answer 3

like this 3(-1)^2-1

Answer 4

its 2 so its even ?

Answer 5

yes it is even
but it is even because f(-x)=3(-x)^2-1=3x^2-1=f(x)

recall (-x)^2=(-1*x)^2=(-1)^2(x)^2=(1)(x)^2=x^2