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Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x. 10x2 + 3x − 4 −40x3 − 12x2 − 4 −10x2 + 3x − 4 10x2 − 3x + 4
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what does the numerator look like?
\[-40x ^{3}-12x +16x\]
it should be -12x^2
ok, and the numerator is -4x
|dw:1430261910441:dw|
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oops yeah thats what it is
so an x will cancel from each term in the numerator
what will that give us?
so we cancel the x's out? is that what your saying?
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