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Mathematics 15 Online
OpenStudy (anonymous):

Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x. 10x2 + 3x − 4 −40x3 − 12x2 − 4 −10x2 + 3x − 4 10x2 − 3x + 4

OpenStudy (anonymous):

what does the numerator look like?

OpenStudy (anonymous):

\[-40x ^{3}-12x +16x\]

OpenStudy (anonymous):

it should be -12x^2

OpenStudy (anonymous):

ok, and the numerator is -4x

OpenStudy (anonymous):

|dw:1430261910441:dw|

OpenStudy (anonymous):

oops yeah thats what it is

OpenStudy (anonymous):

so an x will cancel from each term in the numerator

OpenStudy (anonymous):

what will that give us?

OpenStudy (anonymous):

so we cancel the x's out? is that what your saying?

OpenStudy (anonymous):

@10115658

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