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Mathematics 19 Online
OpenStudy (anonymous):

What is the value of x? Round your answer to the nearest tenth if necessary.

OpenStudy (anonymous):

OpenStudy (anonymous):

@welshfella

geerky42 (geerky42):

Use pythagorean theorem

OpenStudy (anonymous):

@TheSmartOne

geerky42 (geerky42):

\(a^2+b^2=c^2\)

OpenStudy (anonymous):

can you explain how to do that?

geerky42 (geerky42):

\(a\), \(b\) are legs and \(c\) is hypotenuse. So you have \(a=5\), \(b=8\), and \(c=x\) So you have \(x^2 = 5^2+8^2\) Can you solve for \(x\) here?

OpenStudy (anonymous):

yeah.....

geerky42 (geerky42):

Okay, go ahead and solve for \(x\).

OpenStudy (anonymous):

is this it: x≈9.43398113,−9.43398113

OpenStudy (anonymous):

@geerky42 please i really need help

geerky42 (geerky42):

Just ignore negative number because length is never negative. So your answer is \(x \approx9.434\)

OpenStudy (anonymous):

sorry if i got it wrong im really stupid at math

OpenStudy (anonymous):

rounded to the nearest tenth?

geerky42 (geerky42):

You are right, it's just that negative number is not involved here.

geerky42 (geerky42):

No that would be \(9.4\)

geerky42 (geerky42):

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