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What is the value of x? Round your answer to the nearest tenth if necessary.
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@welshfella
Use pythagorean theorem
@TheSmartOne
\(a^2+b^2=c^2\)
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can you explain how to do that?
\(a\), \(b\) are legs and \(c\) is hypotenuse. So you have \(a=5\), \(b=8\), and \(c=x\) So you have \(x^2 = 5^2+8^2\) Can you solve for \(x\) here?
yeah.....
Okay, go ahead and solve for \(x\).
is this it: x≈9.43398113,−9.43398113
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@geerky42 please i really need help
Just ignore negative number because length is never negative. So your answer is \(x \approx9.434\)
sorry if i got it wrong im really stupid at math
rounded to the nearest tenth?
You are right, it's just that negative number is not involved here.
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No that would be \(9.4\)
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