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Mathematics 13 Online
OpenStudy (anonymous):

What is the value of x? Round your answer to the nearest tenth if necessary. @geerky42

OpenStudy (anonymous):

OpenStudy (anonymous):

@geerky42 any ideas?

OpenStudy (anonymous):

you would use the pythagorean theorem of \[a ^{2}+b ^{2}=c ^{2}\] where c is the hypotenuse

geerky42 (geerky42):

pythagorean theorem again. \(a= 14\), \(b = x\), and \(c = 20\)

geerky42 (geerky42):

Solve for x.

OpenStudy (anonymous):

\[14^{2}+b ^{2}=20^{2}\]

geerky42 (geerky42):

^

OpenStudy (anonymous):

is it x≈14.28285686

geerky42 (geerky42):

Yep

geerky42 (geerky42):

Now round to nearest tenth

OpenStudy (anonymous):

14.3

geerky42 (geerky42):

Bingo.

OpenStudy (anonymous):

can you give @graze65 a medal

geerky42 (geerky42):

Sure

OpenStudy (anonymous):

yep i got 100% on the test

geerky42 (geerky42):

Congrats :)

OpenStudy (anonymous):

all thanks to you

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