Question

**CHECK**

Answer 1

Simplify.
\[\frac{ u^2+3u }{ u^2-9} \]

Answer 2

Try factor numerator and denominator

Answer 3

A. \[\frac{ u }{ u-3 }, u \neq -3 and u \neq 3\]
B. \[\frac{ u }{ u-3}, u \neq -3\]
C. \[\frac{ 1 }{ u-3}, u \neq -3\] <---I think its this one
D. \[\frac{ u+3 }{ u-3 }, u \neq -3 and u \neq 3\]