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**CHECK**+MEDAL** Simplify. u^2+3u/u^2−9 A. u/u−3 ,u≠−3andu≠3 B. u/u−3 ,u≠−3 C. 1/u−3 ,u≠−3 D. u+3/u−3 ,u≠−3andu≠3
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C?
how did you get that ?? :-)
My sister googled it :/ :)
hahh let's do it :-) apply difference of square which is \[\huge\rm (a^2 - b^2) = (a+b)(a-b)\]
take square root of first term and square of 2nd term of u^2 - 9 let me know what you get
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I dunno :/ this is my sisters question shes in 9th im in 8th.......
hmmm so probably she is older than you
Right
Is her answer correct?
okay tell her to apply difference of square method |dw:1430345625008:dw| take square of both term write that in parentheses one sign should be negative one positive
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