Question

The coordinates of trapezoid EFGH are E(4, 6), F(2, 3), G(4, 2), and H(8, 4). The image of EFGH under dilation is E'F'G'H'.

If the coordinates of vertex G' are (2, 1), what are the coordinates of vertex H'?

(4, 2)
(2, 1)
(4, 1)
(6, 2)

Answer 1

G(4,2) -> G'(2,1)
you divide by 2

Answer 2

to find H'
divide \((\dfrac{8}{2},\dfrac{4}{2})\)

Answer 3

i think its a

Answer 4

@ireallylikefood it's against the rules to give answers

Answer 5

Well pellet sorry