Question

Choose the equation of the line passing through the point (-1, 7) and perpendicular to y = -negative one fourthx - 5.

y = -4x - 11

y = -4x - 3

y = 4x + 11

y = 4x + 3

Answer 1

@jigglypuff314 , @texaschic101

Answer 2

@TheSmartOne

Answer 3

@Miss.SweetiePie

Answer 4

give me a sec

Answer 5

@campbell_st

Answer 6

first we find the slope of the equation given....y = -1/4x - 5
in y = mx + b form, the slope is in the m position
y = (-1/4)x - 5
y = mx + b
so what is the number in the m position....that is the slope

Answer 7

do you know the slope ?

Answer 8

My guess was C, but I'm not sure.

Answer 9

we will get there....do you know the slope of the equation given ?

Answer 10

No I am not sure.

Answer 11

@texaschic101

Answer 12

ok....let me show you how to do this...
the slope of the equation given is -1/4.....but we are looking for a perpendicular line...so we need the negative reciprocal slope. To find the negative reciprocal, flip the slope and change the sign. So the negative reciprocal of -1/4 is 4/1 (see how I flippped the slope and changed the sign)

now we use y = mx + b
our new slope (m) = 4
now we use the points given (-1,7)...x = -1 and y = 7)
now we sub again
y = mx + b
7 = 4(-1) + b
7 = -4 + b
7 + 4 = b
11 = b

so our perpendicular equation is : y = 4x + 11.......your right, it is C

Answer 13

Wow, thanks!

Answer 14

no problem :)