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OpenStudy (mrhoola):
Topic: BJT (PNP) transistor Given : Beta (current gain) is very high I_base = I_emitter / beta = 0 mA Question : How did they arrive to the voltage V_10 = 0. 73 V Using the voltage divider rule . My calculations arrive me to V_10 = 3.37 V . My work is incorrect , the correct solution is 0.73 V
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