PLEASE HELP!!!! FAN & MEDAL!! *Picture in comments* Part A: What is the approximate length of rod PR? Round your answer to the nearest hundredth. Explain how you found your answer stating the theorem you used. Show all your work. Part B: The length of rod PR is adjusted to 18 feet. If width PQ remains the same, what is the approximate new height QR of the scaffold? Round your answer to the nearest hundredth. Show all your work.
@timo619 @mikeyymonroe @anyone!
ot's the last question on my test and I really need help!
@quickthing @rayne612 @yowasup @iamrobin @openstudier101x @pepermint @SamsungFanBoy I REALLY need help!
I refuse to help you.
@iambatman Please, I need your banarang here. We have a cheater.
wut
What do u need
what tyest
what
nevrrmind i got it
@amistre64 Cheater over here...
still goin at it, arent you? I don't beleive I did anything to you, because theres no reason to report me if no one even gave me an answer. It's not even my test.
TheHangingTree Best Response Medals 0 ot's the last question on my test and I really need help! 22 minutes agoReport Abuse
It's still a test.
use the Pythagorean Theorem to find PR: \[a ^{2}+b ^{2}=c _{2}\]
ohhhh!
please dont post test questions here that is cheating and you can get into seroius consequences we can help on hw and reviews but tests are for you not us to take thank you
http://pages.citebite.com/a4o3b6r4a2tjy Please read the Anti-Cheating Policy of OpenStudy while you are at it.
PR is the hypotenuse, and PQ and QR are the legs, so: \[14^{2}+9^{2}=x ^{2}\] 196+81=\[x ^{2}\] 277=\[x ^{2}\] So, find the square root of 277, to find the length of PR
ill just leave. I said I needed help, not the answers. I don't remember this stuff, it's from 8th grade
thank you so much @openstudier101x
Haha ikr me too, I barely remember but luckily I always manage to keep it in mind bc its really helpful :)
Of course, happy studying! :) @TheHangingTree
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