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Trig Identities Proof: \[\sin^2x+\cos^4x=\cos^2x+\sin^4x\]
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hint: left side= \[\Large {\left( {\sin x} \right)^2} + {\left( {\cos x} \right)^4} = {\left( {\sin x} \right)^2} + {\left( {1 - {{\left( {\sin x} \right)}^2}} \right)^2} = ...?\] please continue
yep now it's easy :) just expand it :)
Okay! I got it! :) Thanks you guys! @Michele_Laino and @rvc
Thank you! :) @esam2
thank you
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