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Solve the equation ln(1+x^2)=1+2lnx,
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@Preetha
@rational
@Michele_Laino
\[\begin{align*} \ln(1+x^2)&=1+2\ln x\\ \ln(1+x^2)&=\ln e+\ln x^2\\ \ln(1+x^2)&=\ln ex^2\\ 1+x^2&=ex^2\\ &\vdots \end{align*}\]
thank you but am not being able to get the right answer... whta answer u"ve got ?
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@iGreen help plz
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