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let f(x)=x^3+ax^2+2a^2x+a such that f(x) has a point of inflection located at x=2. What is the value of a?
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Hint : a necessary condition for inflection point is, the "second derivative must be 0"
Ok so would the derivative be f'(x)=3x^2+6ax+a?
f(x)=x^3+ax^2+2a^2x+a f'(x) = 3x^2 + 2ax + 2a^2 f''(x) = 6x + 2a
set f''(2) = 0 and solve "a"
ok so a is -6?
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Yep!
nice! thanks a lot!
yw
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