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Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x. 10x2 + 3x − 4 −40x3 − 12x2 − 4 −10x2 + 3x − 4 10x2 − 3x + 4
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\[-40x ^{3} - 12x^2 + 16x\div(-4x) \]
is this correct?
you can factor out the 4x on the top quanitiy \[4x(-10x ^{2} - 3x + 4)\div(-4x)\]
do you see something that might cancel?
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