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Mathematics 7 Online
OpenStudy (anonymous):

Find the quotient of the quantity negative 40 times x to the 3rd power minus 12 times x to the 2nd power plus 16 times x all over negative 4 times x. 10x2 + 3x − 4 −40x3 − 12x2 − 4 −10x2 + 3x − 4 10x2 − 3x + 4

OpenStudy (anonymous):

\[-40x ^{3} - 12x^2 + 16x\div(-4x) \]

OpenStudy (anonymous):

is this correct?

OpenStudy (anonymous):

you can factor out the 4x on the top quanitiy \[4x(-10x ^{2} - 3x + 4)\div(-4x)\]

OpenStudy (anonymous):

do you see something that might cancel?

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