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Mathematics 13 Online
OpenStudy (anonymous):

HELP! URGENT!

OpenStudy (anonymous):

Isabella is solving the equation 4x2 = 13x – 3 with the quadratic formula. What values should she use for a, b, and c? (Points : 1) a = 4 b = 13 c = –3 a = 4 b = –3 c = 13 a = 4 b = 3 c = –13 a = 4 b = –13 c = 3

OpenStudy (misty1212):

HI!!

OpenStudy (misty1212):

\[ 4x^2 = 13x – 3\] right?

OpenStudy (anonymous):

help me!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

whoops, yes

OpenStudy (misty1212):

ok dear no problem set it equal to zero \[4x^2-13x+3=0\]

OpenStudy (anonymous):

then I get: x=3,1/4

OpenStudy (misty1212):

\[\huge \color{red}4x^2\color{green}{-13}x+\color{blue}3=0\]\[\huge \color{red}ax+\color{green}bx+\color{blue}c=0\]

OpenStudy (anonymous):

thanks! I have one more!

OpenStudy (misty1212):

you do not get x = anything you have to identify a, b and c did you do that?

OpenStudy (anonymous):

Yes, I did what is the unsimplified solution for 2x2 + 7x – 5 = 0?

OpenStudy (misty1212):

\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with \[a=2,b=7,c=-5\]

OpenStudy (anonymous):

ahhhh okay, thank you so much!

OpenStudy (misty1212):

\[\color\magenta\heartsuit\]

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