Question

8x^2y^2 - 4x^2y - 12xy
--------------------------
4xy

Answer 1

do you just want to simplify it?

Answer 2

4xy[(2xy)-x-3)]/4xy
cancel the 4xy, and you get 2xy-x-3

Answer 3

we can factor out 4xy at numerator, so we can write this:
\[\Large \frac{{8{x^2}{y^2} - 4{x^2}y - 12xy}}{{4xy}} = \frac{{4xy\left( {2xy - x - 3} \right)}}{{4xy}} = ...?\]