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Mathematics 15 Online
OpenStudy (anonymous):

Fan & medal for one question Scores on a test have a mean of 66 and Q3 is 80. The scores have a distribution that is approximately normal. Find the standard deviation. Round your answer to the nearest tenth. 10.5 18.7 20.9 9.4

OpenStudy (anonymous):

mm hard one what do u think?

OpenStudy (anonymous):

I honestly have no idea how to solve this, and help would be greatly appreciated.

OpenStudy (anonymous):

mm idk rly but i might know someone who does one sec @DarkMoonZ

OpenStudy (anonymous):

;-;

OpenStudy (anonymous):

I don't know it either, sorry.

OpenStudy (anonymous):

Q1 is prob. 51. The diff between 81 and 66 is 15. Subtract 15 from 66, you get 51. The average (or mean) is 66. => (51+81)/2=66. this is a start, if it helps

OpenStudy (anonymous):

It's 80, not 81....

OpenStudy (anonymous):

The answer was 20.9

OpenStudy (anonymous):

sorry:'(

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