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The sum of two numbers is 67. The larger number is 4 more than 2 times the smaller. What are the two numbers?
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x = larger number, y = smaller numer x + y =67 2y + 4 = x If you substitute you can solve for both x and y
2y + 4 + y = 67 3y + 4 = 67 minus 4 on both sides 3y = 63 divide by 3 on both sides y = 21 Substitute "y" back in the original equation (x + y =67) x + 21 = 67 minus 21 on both sides x = 46
46 is 4 more than 2 times the smaller number 21, and 46 + 21 = 67. I hope this helped
it did thx @ZDoubleM
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