(D^2+8D-9)Y=0 DIFFERENTIAL EQUATION
BOUNDARIES ARE y(1)=1 y(1)=0
general solution was y=C1e^x+C2e^-9x
y(1)=1 y(1)=0 sic?? y(1)=1 y'(1)=0
AFTER APPLYING THE BOUNDARY CONDITIONS I GOT 1=C1e+C2e^-9 0=C1e-9C2e^-9
read my post again. there is a typo in your IV's.
NOW I HAVE TO FIND THE VALUES OF C1 AND C2 HERE I THINK IM DOING SOME MISTAKE CAN YOU HELP PLEASE
all caps is not an effective means of comunication ...
sorry
your setup is fine, you have a system of 2 eqs in 2 unknown, solve by your favorite algebra method
i subtracted eq1 from eq2
simultaneous method
then solve for c2
but im getting a wrong answer can you please show me the solution so i can see what mistake i have made
show me wht you did after subtraction, its that way you see your own error
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your subtraction is in error
-1-9 = -10
can you please show it in the simultaneous method format please
write your work out ... and you shuld see it quite clearly
i tried its all jumbled up
i cant help you with your organizational skills. you ahve the correct system, you have the correct enough process ... youve messed up on your subtraction.
But you have to wait ill try again
type it out instead of trying to draw it if it helps
youve got the correct results on your paper now, what do we do?
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