Question

Help, please! :)

Choose the correct simplification of the expression the quantity a to the 3rd power over b to the 7th power all raised to the 2nd power.

a to the 5th power over b to the 9th power
a over b to the 14th power
a to the 6th power over b to the 14th power
a6b14
10. [7.04] Choose the correct simplification of the expression 6 times b all over a to the power of negative 9.

a to the 9th power times b all over 6
6 times b all over a to the 9th power
Already simplified
6a9b

Answer 1

\[(\frac{ a ^{3}\ }{ b ^{7} } )^2\]

Answer 2

Like that?

Answer 3

yes.

Answer 4

@johnweldon1993 could you help? :)

Answer 5

\[\frac{a^{3*2}}{b^{7*2}}\]

Answer 6

sup?

Answer 7

or you can think of it like this
\[\frac{a^3}{b^7}*\frac{a^3}{b^7}\]