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Algebra
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how would you find an equivalent expression to 3c(1/3d-9)-7(c+1)+d(c+4)
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what do you have so far
we tried distributing but we havnt gotten any of the answer choices
need to see the answer choices
A) 2cd-34c+4d-7 B) 2cd-7c-4 C) 2cd+34c+4d+7 D) 2cd+8c+4
could you explain how you set that up? we havnt learned much this year and we have an EOCT on tuesday.
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hold on im dumb
haha ok thank you
is it 1/3d-9 or 1/(3d-9)
3c(1/3d-9)
\[3 \frac{ 1 }{ 3d-9 } - 7(c+1)+d(c+4)\]
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\[=\frac{ 1 }{ d-3 } -7c -7 +cd + 4d\]
\[= \frac{1+ (d-3)(-7c-7+cd+4d) }{ (d-3) }\]
oook thanks
id keep going but the problem looks weird for some reason
yeah thanks tho
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