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Integrate:
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\[\int\limits \sqrt{1+\cos^2x}*\sin(2x)*dx\] ????
sin2x=2sinx*cosx it is standard formula
yes i did it
put \[1+\cos^2x=t^2\]
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try it now and tell what u got after differentiation
okay
differentiate it
i got 2tdt =-2cosxsinx
2t*dt=-2cosx*sinx*dx
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plug it in integration
okay let me do it
sure... i will wait :)
i got -2/3(1+cos^2x)^3/2 +c
\[-\frac{ 2 }{ 3}(1+\cos^2x)^{\frac{ 3 }{ 2 }}+c\] yes you got it right :)
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