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the lateral area of a frustum of a regular triangular pyramid is 1,081 cm^2 and the altitude and lateral edge are 24 cm and 26 cm, respectively. Find the length of the sides of the bases.
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@ganeshie8
The answer must be 6.03 and 23.35 cm, based on the book
|dw:1430572776127:dw|
|dw:1430572851838:dw|
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|dw:1430572916880:dw|
that length would be \(10\) because \[\sqrt{26^2-24^2} = \sqrt{100}=10\]
yup
see how that length, lateral edge and altitude form a right triangle ?
yup
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|dw:1430573066513:dw|
good, in that 30-60-90 triangle, can you find the remaining two side lengths ?
|dw:1430573128670:dw|
Yes, we're done with that triangle.
|dw:1430573205478:dw|
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