Question

What are the x-coordinates of the solutions to this system of equations?

x2 + y2 = 36
y = x - 6

2 and 0
6 and 2
6 and -2
6 and 0

Answer 1

Please help 😦

Answer 2

replace y with x-6 in the first equation and solve for x

Answer 3

^then simplify then factor and solve

Answer 4

answer is B

Answer 5

don't give answers dear
show how you get it

Answer 6

\[x^2+(x-6)2=36\\ x^2+x^2-12x+36=36\]
\[2x^2-12x=0 \\ 2x(x-6)=0\]
\[2x=0~~or ~~x-6=0\]

Answer 7

I got 6, -7. I don't know how I went wrong or where.

Answer 8

finish up the work

Answer 9

that's incorrect

Answer 10

Ahhh, I see what I did.