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Find the rectangular coordinates of the point with the polar coordinates. (3, 2pi/3)
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x=r cos theta ; y = r sin theta
r = 3
theta = (2pi/3)
x=? y=?
x= 3 cos (2pi/3) ; y = 3 sin (2pi/3)
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(x,y) = 3 *cos 120 ; y = 3*
y=3*sin 120
Cos120=? @katiexo
Sin120=?
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cos of 120 = .8142? sin 120 = .5806?
i'm in radians
Cos120=cos(90+30)=?
-1/2
x=?
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3
No
-3/2
wait x=-3/2 and since sin(120) is sqrt of 3/2 then y = 3*sqrt of 3/2? @shamim
Correct!!!!
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Thanks!
Anyway i m in bus travelling to my college. So late to reply
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