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OpenStudy (anonymous):
OpenStudy (anonymous):
B
OpenStudy (anonymous):
could you explain your answer plz?
OpenStudy (anonymous):
because your mean should always be larger than your median
OpenStudy (amistre64):
sigh ... not gonna agree with that at all
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OpenStudy (anonymous):
why not?
jimthompson5910 (jim_thompson5910):
see attached
OpenStudy (amistre64):
outliers skew the mean .... you see how long that one whisker is? and how short the other is?
OpenStudy (anonymous):
yes i do, and thank you @jim_thompson5910
OpenStudy (amistre64):
that outlier is pulling the mean out of alignment which gives us a false reading
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jimthompson5910 (jim_thompson5910):
yw
OpenStudy (anonymous):
sorry wasn't really thinking haven't slept in 18 hrs
OpenStudy (anonymous):
oh okay, thank you
ah it's okay
OpenStudy (anonymous):
so who do i give the medal to, @jim_thompson5910 or @amistre64 ?
OpenStudy (amistre64):
whoever you want ...
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OpenStudy (anonymous):
@jim_thompson5910 can you give a medal to amistre plz??
OpenStudy (anonymous):
I'll give one to jim thompson you give to amistre
OpenStudy (anonymous):
since I screwed up
OpenStudy (anonymous):
thank you, but could you give it to amistre instead? i already gave it to jim
OpenStudy (anonymous):
sure
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OpenStudy (anonymous):
yay, thank you
OpenStudy (anonymous):
you didnt mess up, you were just sleepy
OpenStudy (anonymous):
no problem any questions with numbers I can help, Im great with numbers
OpenStudy (anonymous):
The number of job applications a store received each day over a two-week time period is shown.
3 8 8 6 10 9 5 9 4 5 9 4 4 7
Which measure or measures of central tendency best reflect the data?
Choose all answers that are correct.
mean
median
mode
OpenStudy (anonymous):
it would be mean because you are trying to find the average amount of apps brought in each day
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