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Solve (z+ 7)2 = 3. Need help quick! Will MEDAL
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(z+7)^2=3
\[(z+7)^2=3\]
Yup
move the square to the other side
Ok \[z+7=9\]
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no
z+7=3^2?
\[(z+7)^2=3\]
That's what we started with
\[z+7 = \sqrt{3}\]
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Ahh ok
then subtract 7 from both sides?
yup
So\[-7\]
Oops
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\[z=\sqrt{3-7}\]
\[-7\pm \sqrt{3}\]
\[z= \sqrt{3} -7\]
yeah that is correct
Awesome thanks :D
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no problem
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