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OpenStudy (anonymous):
Tan (x/2)= square root of 3 so far I have x can = π/3 and 4π/7 I am lost to do next.
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OpenStudy (anonymous):
4π/3 I mean
OpenStudy (loser66):
Your original is (x/2) not x, hence for (x/2) = pi/3, x = 2pi/3 for (x/2) = 4pi/3, x = 8pi/3 2pi/3 and 8pi/3 has the same destination.
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