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Mathematics 14 Online
OpenStudy (anonymous):

FAN AND MEDAL!!!!!!!

OpenStudy (anonymous):

Find the perimeter of the rhombus QRST.

OpenStudy (anonymous):

these are the choices 38 76 56 361

OpenStudy (anonymous):

whats the equation??

OpenStudy (igreen):

All 4 sides are congruent.

OpenStudy (igreen):

Therefore \(\sf 2x - 9 = x + 5\). Solve for 'x'

OpenStudy (anonymous):

ok

OpenStudy (javk):

well in a rhombus all four sides are equal

OpenStudy (anonymous):

x=14 @iGreen

OpenStudy (igreen):

Yep, you got it.

OpenStudy (igreen):

Now plug it back in 2x - 9 2(14) - 9

OpenStudy (anonymous):

thanks so much. you work magic !!!!

OpenStudy (anonymous):

ok

OpenStudy (igreen):

Or just 14 + 5

OpenStudy (anonymous):

19

OpenStudy (igreen):

Yes, so each side is 19, and the perimeter is 4a, where 'a' is the length of the side. 4 * 19 = ?

OpenStudy (igreen):

That will be our answer.

OpenStudy (anonymous):

76

OpenStudy (igreen):

Yep, you got it.

OpenStudy (anonymous):

omg thanks so much !!!!! i love it that you dont just give answers because that dosent help at all

OpenStudy (igreen):

Yes, that's what everyone is supposed to do.

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