Question

In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and
m∠COD = 16°, what is m∠CED?

37
48
53
62

Answer 1

picture @jackmullen55

Answer 2

I want to say 53 but I'm no 100% sure

Answer 3

Okay

Answer 4

@Zweifel do you know

Answer 5

Give me a minute i like taking my time and thinking about them slowly. Sorry i'm not fast

Answer 6

Okay that's fine

Answer 7

Arc AB would equal 90 because from the center the arc is the same as the angle. So that means that the angle would have to be 90 when multiplied by two so i would go with 48 even though it isn't exactly what i would expect i would still go with it. But when i measured it with my protractor i get an answer just less than sixty. But logically i would go with 48.

Answer 8

That's my synopsis... Granted i am still capable to make mistakes so i could be wrong.

Answer 9

yourwrong, its not 48

Answer 10

53 is the correct answer :)