Question

Geometry Help Please! MEDAL

Answer 1

First plug point (5, -2) and m = 2/5 into slope intercept form
y = mx + b
-2 = (2/5)(5) + b
-2 = 2 + b

Subtract 2 from both sides
b = -4

This yields
y = (2/5)x - 4

Next manipulate the equation into standard form which is
Ax + By = C
Where A,B and C are integers and A is positive

Multiply both sides of y = (2/5)x - 4 by 5
5y = 2x - 20

Subtract 5y from both sides
2x - 5y - 20 = 0

Add 20 to both sides
2x - 5y = 20 <-----

Answer 2

@FlashBT3

Answer 3

I found the answer and closed the question, I'm done with it