Question

Jim makes the chart shown below to prove that triangle APD is congruent to triangle BPC:
Statements Justifications
In triangles APD and BPC; DP = PC Sides of equilateral triangle DPC are equal
In triangles APD and BPC; AD = BC Sides of square ABCD are equal
In triangles APD and BPC; angle ADP = angle BCP Angle ADC = angle BCD = 90° and angle ADP = angle BCP = 90° - 60° = 30°
Triangles APD and BPC are congruent SSS postulate

He writes DP = PC instead of DP = PB.
He writes AD = BC instead of AD = PC.
He assumes the measure of angle ADP and angle BCP as