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REALLY NEED HELP! WILL MEDAL U! Use the quadratic formula to solve 2y^2 – 3y = 2 A {½, –2} B {–½, –2} C {½, 2} D {–½, 2}
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What is the quadratic formula ?
isn't up in the description box
I know the formula
hahaha.. hence, medal for you @wolf1728
a=2 b=-3 c=-2 [x=-b +-sq root(b^2 -4*a*c)] / 2*a
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[x = --3 +-sq root(9 -4*2*-2)] / 2*2 x = [3 +- sq root (9 +16)] / 4 x = 3 + 5 / 4 x=2 x = 3-5 /4 x= -.5
That's D
nbarrera - do you agree?
yes
okay then :-)
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