Find the value of each of the other 5 trig functions for an angle 'X', w/out finding X, given: cos(x)=-sq. rt.5/3 & cot(x)>0
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fins the missing side via pythagoras then you can find any trig ratio you need
i put sinx=2/3 and it was marked wrong, any ideas?
if cot is + and cos is +, then sin is ?
positive?
\[\cot(x)=\frac{\cos(x)}{\sin(x)}\] cos(x)/sin(x) is positive if both cos(c) and sin(x) are positive or cos(x)/sin(x) is positive if both cos(X) and sin(x) are negative
well okay and if cot is + and cos is -, then sin is?
negative
right you have here in your problem cot is positive and cos is negative so your sin value will be negative as well
if you draw it on a graph, will it be in quadrant 2? if it is wouldnt the adjacent side be negative?
you will be in quadrant 3 because both sin and cos are negative
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