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Solving logarithm help?
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wht grade is tht
\[3\log (2x)=4\] \[\log (2x)=\frac{4}{3}\] change into exponent form : \[2x=10^{\frac{4}{3}}\] \[x=\frac{10^{\frac{4}{3}}}{2}\] use your calculator to simplify
yeah you can do this :)
wait how'd you turn 4/3 to 10^4/3 ?
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we have a rule for that
\[\log x = a\] is same as \[x = 10^a\]
btw, the default base for log is 10
Oh okay now I get it thanks @rational
np:)
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@rational I got 6.66 repeating, closest answer to that is C, is that it?
the answer is not 6.66 it's 10.772
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