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OpenStudy (anonymous):
two identical masses are traveling down a slope. One mass is traveling twice as fast as the other mass. How does the kinetic energy of one compare to the other
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OpenStudy (timbo5lice):
i think you should have put this in the science section but ill help you and welcome to open study(:Snow lookin at it the lower object: KE = 0.5m*V^2. and looks like the Faster object: KE = 0.5m*(2V)^2 = 0.5m*4*V^2. so now you move it down and reveiw what u have KE = 1/2*m*v^2 If v is 2x as much then KE is 4x as much (: hope this helps!!!.
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