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i need help please
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A.
see the slope should be -ve in the eqn. and do you know why?
yes but its hard @lall
the line runs through half of the one and through the 1 can u help me with more can i tag u
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see slope is tanx
here in this case angle x is greater than 90' hence tanx = tan(90+a) = - tana hence slope is -ve.
now tan ratio of any angle is perpendicular upon base from graph perpendicular is 1 base is in fraction may be 1/3 hence tan a =-1/(1/3) = -3 sorry so i think D. is the corrct option
A. was i think wrong you can check from ans book
@narissa
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