Question

Calculate the discriminant and use it to determine how many real-number roots the equation has.

3x^2 – 6x + 1 = 0

(Points : 4)
three real-number roots
two real-number roots
one real-number root
no real-number roots

Answer 1

\(\bf {\color{blue}{ 3}}x^2{\color{red}{ -6}}x{\color{green}{ +1}}\qquad discriminant\implies {\color{red}{ b}}^2 -4{\color{blue}{ a}}{\color{green}{ c}}
\)

what does the value mean?
well -> http://www.regentsprep.org/regents/math/algtrig/ate3/discriminant.htm