Question

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Answer 1

\[\sin2x-\cos x=2\sin x\cos x-\cos x=(2\sin x-1)\cos x\]

Answer 2

this is similar to what you had before it is just that this one is not and equation

Answer 3

they just want you to simplify using double angle identity

Answer 4

\(\bf \sin2x-\cos x=2\sin x{\color{brown}{ \cos x }}-{\color{brown}{ \cos x}}=(2\sin x-1){\color{brown}{ \cos x}}\)

notice the common factor, thus

Answer 5

yeah so is that the final answer

Answer 6

yes because thats an expression in only sin x and cos x

Answer 7

thanks :)