Question

10. If an employee walks at 2/3 of his usual speed, he gets late to the office by 15 mins. What time does he usually take to reach the office?
A. 10 min.
B. 30 min
C. 25 min,
D. 35 min

Answer 1

the distance is the same he walks D
D= speed *time= say x*t originally
D=(2/3)*x (t+15) equate the distances
xt=(2/3)*x)(t+15) let x=6 it could be anything
6t=4(t+15)
2t=60
t=30 the time it normally takes
check my reasoning

Answer 2

thanks for explaining