10. If an employee walks at 2/3 of his usual speed, he gets late to the office by 15 mins. What time does he usually take to reach the office?
A. 10 min.
B. 30 min
C. 25 min,
D. 35 min

Question

10. If an employee walks at 2/3 of his usual speed, he gets late to the office by 15 mins. What time does he usually take to reach the office?
A. 10 min.
B. 30 min
C. 25 min,
D. 35 min

anonymous · Answer

the distance is the same he walks   D
D= speed *time=  say x*t   originally
D=(2/3)*x (t+15) equate the distances
xt=(2/3)*x)(t+15)       let x=6 it could be anything
6t=4(t+15)
2t=60
t=30   the time it normally takes   
check my reasoning

anonymous · Answer

thanks for explaining