Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

solve the quadratic will medal question in comments

OpenStudy (anonymous):

|dw:1431014207848:dw|

OpenStudy (anonymous):

-6x btw

OpenStudy (anonymous):

is it \[x ^{2}-6x+9=0\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

\[x ^{2}-3x-3x+9=0\]

OpenStudy (anonymous):

\[x (x-3)-3(x-3)\]

OpenStudy (anonymous):

Im not sure if thats right because it is not the type of solution I am looking for but thank you anyways

OpenStudy (anonymous):

(x-3)(x-3)=0 x=3 & x=3

OpenStudy (anonymous):

it is simply \[(x-3)^{2}=0\]

OpenStudy (anonymous):

x=3

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!