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What is the tenth term of the geometric sequence 3, 6, 12, 24, 48, … ?
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nth term = a*r^(n-1) where a = first term and r = common ratio here a = 3 and r = 6/3 = 2
10th term = 3* 2^(10-1)
1536?
grab your calculator and see what you get..
correct
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thanks
yw
3 = 3* (2^(1-1)) n=1 3*2 = 3* (2*(2-1)) n=2 3*2*2 = 3* (2*(3-1)) n=3 3*2*2*2 = 3* (2*(4-1)) n=4 then 3*( 2^(N-1)) if n-->1
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