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sin(2cos^-1 15/17) find the value Please help!!??
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let u=arccos(15/17) draw a right triangle
cos(u)=15/17
recall sin(2u)=2sin(u)cos(u)
so you will want to find sin(u) from your right triangle
then multiply your 3 factors there
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So what would the answer be... And how would I actually work ...?! Thanks
Have you tried anything I wrote yet?
you need to evaluate 2sin(u)cos(u) given cos(u)=15/17 (use quadrant one to build right triangle)
yes so it is 240/289
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