Question

A two digit positive number such that the products of its numbers is 6.If 9 added the number the digits, interchange places.Find the original number.

Answer 1

@Data_LG2

Answer 2

@The_Joker<3

Answer 3

Let \(10a+b\) denote the original number, with \(a\) one of the numerals 1-9 and \(b\) one of \(0-9\).

You have the following system of equations:
\[\begin{cases}ab=6\\
10a+b+9=10b+a\end{cases}\]

Answer 4

Oh, and now you know \(b\) must be a numeral from 1-9, it can no longer be 0.

Answer 5

{ a b = 6, 9 + a + b = 10 b + a}
a = 6, b = 1