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Algebra
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log2 3+log2 a= log2 10 a. 0.3 b. 20 c. 7 d. 3.3333
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Remember that when you add logs of the same base, you multiply what's in the log. Since both these logs have base a, it's the same as saying that: log2(3a) = log2(10) Cancel out the logs to get: 3a = 10 Divide both sides to get: a = 10/3
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