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Mathematics 10 Online
OpenStudy (mathmath333):

geometry question

OpenStudy (mathmath333):

\(AB\) is the diameter .and \(AB\) parrellel \(PQ\).Find \(\angle BPQ\)

OpenStudy (mathmath333):

|dw:1431121355244:dw|

OpenStudy (loser66):

|dw:1431122888459:dw|

OpenStudy (loser66):

\(\angle ABP =\angle BPQ\) since AB//PQ ok?

OpenStudy (loser66):

\(\angle APB =90^0\)

OpenStudy (loser66):

\(\angle BAP =\angle BRP=80^0\) they strength the same arc BP

OpenStudy (loser66):

Hence \(\angle APB =10^0\)

OpenStudy (mathmath333):

COOL

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