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Am I correct: I got 3.96240625 which is 3.9624
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how did you get that answer ? did you apply change of base formula ?? :-)
yes.. but i dont understand
bec there are two method to solve exponential equation
okay what's the change of base formula ?
ln(4z)=ln(243)
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zln(4)=ln(243)
2zln(2)=ln(243)
okay so you can divide both side by ln 4
hmm 2 ??
2zln(2)=1(5ln(3))
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no 2?
change of base formula \[\huge\rm log_a b = \frac{ \log b }{ \log a }\] that's it
z=5ln(3)//////////2ln(2)
how did you get 5 ? z= 5ln(3) ^ ?
here: The left-hand side of the equation is equal to the exponent of the logarithm argument because the base of the logarithm equals the base of the argument. zln(4)=ln(243)
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|dw:1431182042405:dw| first of all change to log form
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