Question

Trig! :)

Answer 1

@zepdrix do you have more time? :) @freckles ?

Answer 2

aww got it *i guess* :D

Answer 3

r u familiar with this formula ?\[\huge\rm cos ~2x = \cos^2 x - \sin^2 x\]
and sin^2 theta = ?

Answer 4

sin^2(theta)=cos2x-cos^2x ?

Answer 5

hmm \[\huge\rm sin^2 + \cos^2 = 1\]
i mean when you solve this equation for sin^2 what would you get
other one that i posted is for cos(2 theta) :-)

Answer 6

oh haha wait. I don't know.

Answer 7

just subtract cos^2 both side ..

Answer 8

oh gosh, sorry. Tired.
sin^2=1-cos^2

Answer 9

yeah right now replace \[\rm cos(2 \theta)\] by cos^2 - sin^2
and sin^2 by 1-cos^2 in the equation