Question

Find the equation of the quadratic function with zeros -4 and 4 and vertex at (0, -16)

Answer 1

help

Answer 2

how

Answer 3

you can plug in either zero into the vertex form

Answer 4

is the answer
y = x^2 - 16
or
y = -x^2 - 16

Answer 5

Vertex form:
$$
\Large y = a(x-h)^2 + k
$$
y = a ( x - 0)^2 - 16
y = a x^2 - 16

now plug in (4,0) or (-4,0) and solve for `a`

Answer 6

thanks

Answer 7

you should get a = 1

Answer 8

so the answer is y= x^2 -16 ?