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Would like help on lower confidence bound based on chi square method? Photo attached.
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My X^2 = 33.196 since i am only considering one side?
so alpha = .10, and we have dF= 24 right?
33.196 = X^2 \[\chi^2<\frac{(n-1)s^2}{\sigma^2}\] \[\sigma^2<\frac{(n-1)s^2}{\chi^2}\]
24 (2.03)/33.196 seems to be all the parts ...
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Thanks, this is my answer. I wasn't sure.
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